(5x+4)(3x^2-20x+25)=0

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Solution for (5x+4)(3x^2-20x+25)=0 equation: 


Simplifying
(5x + 4)(3x2 + -20x + 25) = 0

Reorder the terms:
(4 + 5x)(3x2 + -20x + 25) = 0

Reorder the terms:
(4 + 5x)(25 + -20x + 3x2) = 0

Multiply (4 + 5x) * (25 + -20x + 3x2)
(4(25 + -20x + 3x2) + 5x * (25 + -20x + 3x2)) = 0
((25 * 4 + -20x * 4 + 3x2 * 4) + 5x * (25 + -20x + 3x2)) = 0
((100 + -80x + 12x2) + 5x * (25 + -20x + 3x2)) = 0
(100 + -80x + 12x2 + (25 * 5x + -20x * 5x + 3x2 * 5x)) = 0
(100 + -80x + 12x2 + (125x + -100x2 + 15x3)) = 0

Reorder the terms:
(100 + -80x + 125x + 12x2 + -100x2 + 15x3) = 0

Combine like terms: -80x + 125x = 45x
(100 + 45x + 12x2 + -100x2 + 15x3) = 0

Combine like terms: 12x2 + -100x2 = -88x2
(100 + 45x + -88x2 + 15x3) = 0

Solving
100 + 45x + -88x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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